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Sep 26, 2018 at 3:00 answer added Ian Agol timeline score: 3
Apr 22, 2016 at 5:54 answer added Daryl Cooper timeline score: 3
Aug 19, 2015 at 22:17 vote accept NWMT
Aug 19, 2015 at 22:16 history edited NWMT CC BY-SA 3.0
Added explanation of misunderstanding
Aug 19, 2015 at 17:51 comment added Sam Nead Just to make things super clear, I edited your post to use the phrase "immersed boundary slope" (as opposed to "embedded boundary slope", etc). This follows Maher's usage.
Aug 19, 2015 at 17:34 history edited Sam Nead CC BY-SA 3.0
immersed slope -> immersed boundary slope
Aug 19, 2015 at 17:30 answer added Sam Nead timeline score: 3
Aug 19, 2015 at 17:28 comment added NWMT @Sam Nead. Thank you for the terminology suggestion. I made the edit. For my specific application $M(\gamma)$ has a (non-cyclic) free fundamental group, in fact it is a doubled handlebody (i.e. Heegard glueing along identity identity). In particular my $M(\gamma)$ isn't hyperbolic, in fact not even prime.
Aug 19, 2015 at 17:23 history edited NWMT CC BY-SA 3.0
changed "boundary slopes" to "immersed slopes"
Aug 19, 2015 at 17:00 comment added Sam Nead Just as a matter of terminology - almost everybody uses "boundary slope" to refer to the slopes that occur as the boundaries of embedded essential surfaces. So you should rewrite your question to talk about, say, "immersed slopes" or some similar construction.
Aug 19, 2015 at 16:52 comment added Sam Nead You have to add some condition on $\gamma$. After all, it could be that $M(\gamma)$ is the three-sphere -- in that case the fundamental group is trivial, so in particular it has no non-trivial free subgroups.
Aug 19, 2015 at 16:12 history edited NWMT CC BY-SA 3.0
closed surface -> closed 3-manifold (typo)
Aug 19, 2015 at 1:15 history asked NWMT CC BY-SA 3.0