Timeline for Faithful linear representation of a nilpotent Lie algebra
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 16, 2015 at 1:49 | vote | accept | Jianrong Li | ||
| Aug 15, 2015 at 19:55 | comment | added | YCor | Take the invertible derivation mapping $e_i$ to $ie_i$, thus defining a 6-dimensional semidirect product of your Lie algebra with a 1-dimensional Lie algebra. The resulting Lie algebra has zero center and hence its adjoint representation is faithful (and easily computable). | |
| Aug 15, 2015 at 13:29 | answer | added | Dietrich Burde | timeline score: 6 | |
| Aug 15, 2015 at 12:45 | history | asked | Jianrong Li | CC BY-SA 3.0 |