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Apr 13, 2017 at 12:19 history edited CommunityBot
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Aug 12, 2015 at 14:49 comment added Tito Piezas III @NoamD.Elkies: Oh, I think I understand. I believe I just used $m=3$ in the group law in my post, but using $m=5$ will be a different matter. So I guess the answer to my second question is indeed "yes", as long as I stick to $m\leq4$.
Aug 12, 2015 at 14:37 comment added Noam D. Elkies Sorry, I meant multiplication by 5 in the group law, as I see that Felipe Voloch already suggested. (And you must have meant g and h to have a non-solvable group.)
Aug 12, 2015 at 13:20 comment added Noam D. Elkies Take a random elliptic curve and use multiplication by 5.
Aug 12, 2015 at 13:02 history edited Tito Piezas III CC BY-SA 3.0
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Aug 12, 2015 at 12:58 comment added Tito Piezas III @FelipeVoloch: Thanks. Would you have at hand an example of an explicit elliptic curve and a transformation with $h(x)$ having a non-solvable group? (P.S. I've also added a question 2. Maybe the answer to the second is a "yes".)
Aug 12, 2015 at 12:54 history edited Tito Piezas III CC BY-SA 3.0
Added question 2.
Aug 12, 2015 at 12:14 comment added Felipe Voloch Not in general. Your $f(x)$ is the $x$-coordinate of an endomorphism of the elliptic curve and $h$, for instance, has roots giving the $x$-coordinates of the kernel of the endomorphism and the Galois group is a subgroup of the automorphism group of said kernel. Sometimes this is solvable but if the endomorphism is multiplication by $m$ for some large $m$, it won't be.
Aug 12, 2015 at 4:59 history asked Tito Piezas III CC BY-SA 3.0