Timeline for Second order differentiability of subharmonic function almost everywhere?
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
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| Feb 29, 2020 at 16:29 | comment | added | Piotr Hajlasz | @AlexandreEremenko In fact a weaker version of Aleksandrov's differentiability is true, see my answer. | |
| Feb 29, 2020 at 16:22 | answer | added | Piotr Hajlasz | timeline score: 3 | |
| May 23, 2018 at 9:19 | comment | added | user111 | @Alexandre Eremenko, I guess a subharmonic function can be discontinuous quasi-everywhere (not everywhere). | |
| May 9, 2018 at 13:56 | vote | accept | student | ||
| May 9, 2018 at 9:41 | answer | added | user111 | timeline score: 7 | |
| Aug 12, 2015 at 18:59 | comment | added | Alexandre Eremenko | The answer is no. The distributional second derivative can be ARBITRARY positive measure. BTW, a subharmonic function can be discontinuous everywhere. | |
| Aug 12, 2015 at 1:26 | history | edited | student | CC BY-SA 3.0 |
edited title
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| Aug 12, 2015 at 1:25 | comment | added | student | @Alexandre Eremenko, sorry I didn't say it clearly in the previous title. I'm asking whether subharmonic function has second derivatives almost everywhere. If not true, does it have some fine properties? | |
| Aug 12, 2015 at 1:03 | comment | added | Alexandre Eremenko | Even the first derivative of a subharmonic function is not defined pointwise. But of course all derivatives exist as Schwartz distributions. | |
| Aug 12, 2015 at 0:15 | history | asked | student | CC BY-SA 3.0 |