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Aug 29, 2015 at 2:08 vote accept QSR
Aug 28, 2015 at 12:05 review Suggested edits
Aug 28, 2015 at 12:29
Aug 10, 2015 at 5:38 comment added user43326 See www.math.uchicago.edu/~may/BOOKS/homo_iter.pdf chapter 4. The base point of $S^0$ is [0]. [-1] is the component of the degree -1 map.
Aug 10, 2015 at 3:16 comment added QSR Are the algebra generators of the form $Q^{I_1}Q^{I_2}\cdots Q^{I_r}([1])$ and $Q^{I_1}Q^{I_2}\cdots Q^{I_r}([-1])$, instead of $Q^{I_1}Q^{I_2}\cdots Q^{I_r}([1])$ and $[-1]$?
Aug 10, 2015 at 3:13 comment added QSR Thanks! Does $[-1]$ mean the base point of $S^0$? Why the $Q^I$'s do not act both on $[1]$ and $[-1]$, but only act on $[1]$?
Aug 10, 2015 at 2:21 vote accept QSR
Aug 10, 2015 at 3:11
Aug 9, 2015 at 14:56 history answered user43326 CC BY-SA 3.0