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Aug 25, 2015 at 6:46 vote accept David Sun
Aug 25, 2015 at 5:07 vote accept David Sun
Aug 25, 2015 at 5:07
S Aug 9, 2015 at 15:53 history suggested David Sun CC BY-SA 3.0
Change the exponent of $\zeta$ from $3k$ to $-3k$ in the line below the calculation of conjugation.
Aug 9, 2015 at 15:42 review Suggested edits
S Aug 9, 2015 at 15:53
Aug 8, 2015 at 16:45 history edited Peter Mueller CC BY-SA 3.0
deleted 52 characters in body
Aug 8, 2015 at 15:53 comment added Peter Mueller @David Sun: Yes, I fixed the typo.
Aug 8, 2015 at 15:44 history edited Peter Mueller CC BY-SA 3.0
added 199 characters in body
Aug 8, 2015 at 15:34 comment added David Sun Thank you very much Peter! Your approach solved the $n \neq 0$ (mod 3) case beautifully! While in your generalized identity, did you mean $3(\zeta z)^{n/3}+1$ on the 2nd line?
Aug 8, 2015 at 14:22 history edited Peter Mueller CC BY-SA 3.0
added 104 characters in body
Aug 8, 2015 at 14:14 history edited Peter Mueller CC BY-SA 3.0
added 812 characters in body
Aug 8, 2015 at 10:41 history answered Peter Mueller CC BY-SA 3.0