Timeline for When $mB \neq B$? $m$ is a maximal ideal of $A$, $A \subseteq B$
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
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| Aug 26, 2015 at 16:43 | vote | accept | user237522 | ||
| Aug 8, 2015 at 23:21 | comment | added | user237522 | Thanks!! When I wrote "Any other ideas are welcome", I meant that I suspect there exist other cases (=not f.f. not integral) where $mB \neq B$; your nice example is (probably) one of them, so it may serve as an answer. However, it would be even nicer to know if one can characterize all (commutative) ring extensions $A \subseteq B$ such that $mB \neq B$. Namely, if one can say that faithfully flat, integral and ... are precisely the extensions that satisfy $mB \neq B$. That's what I originally tried to ask (and hoped there exists a paper on this question, which I am not aware of) | |
| S Aug 7, 2015 at 15:31 | history | answered | Donu Arapura | CC BY-SA 3.0 | |
| S Aug 7, 2015 at 15:31 | history | made wiki | Post Made Community Wiki by Donu Arapura |