Timeline for Complete non-isomorphic lattices with injective complete homomorphisms between them?
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Aug 7, 2015 at 13:14 | comment | added | Adam Przeździecki | @Dominic van der Zypen please unaccept this answer so that I can delete it. | |
| Aug 7, 2015 at 11:49 | history | edited | Adam Przeździecki | CC BY-SA 3.0 |
added 270 characters in body
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| Aug 7, 2015 at 11:41 | comment | added | Adam Przeździecki | I see - I missed that point. So we need both $K$ and $L$ to be disconnected. Please write your answer and I will delete mine. | |
| Aug 7, 2015 at 11:39 | comment | added | Eric Wofsey | That is not a homomorphism; it does not preserve the maximal element. | |
| Aug 7, 2015 at 11:38 | comment | added | Adam Przeździecki | Oh, yes. Or even simpler: $K=[1,2]$ and $L=\{0\}\cup[1,2]$. Referring to your question: this is the identity $[0,1]\to\{0\}\times[0,1]$. | |
| Aug 7, 2015 at 11:32 | comment | added | Eric Wofsey | How do you get a complete injective homomorphism $K\to L$? For a simpler example that does work, just take $K=\{0\}\cup[1,2]$ and $L=\{-1,0\}\cup[1,2]$. | |
| Aug 7, 2015 at 11:23 | vote | accept | Dominic van der Zypen | ||
| Aug 7, 2015 at 11:23 | history | answered | Adam Przeździecki | CC BY-SA 3.0 |