Timeline for understanding geometry of eigen values of Ricci tensor [closed]
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 18, 2015 at 18:18 | history | closed |
Will Sawin Stefan Waldmann Alex Degtyarev Ricardo Andrade Johannes Hahn |
Needs details or clarity | |
| Aug 12, 2015 at 3:04 | review | Close votes | |||
| Aug 18, 2015 at 18:18 | |||||
| Aug 6, 2015 at 4:08 | comment | added | debabrata chakraborty | yes I got it.Can you give me some reference where this is clarified vastly. | |
| Aug 5, 2015 at 20:00 | comment | added | Ryan Budney | The lowest eigenvalue gives you a lower bound of the Ricci tensor's values (with input on the unit sphere). Is that what you are interested in? | |
| Aug 5, 2015 at 19:26 | comment | added | Deane Yang | If you fix a vector $v$, then, up to a scalar factor, $Rc(v,v)$ is the average sectional curvature of tangent 2-planes containing $v$ | |
| Aug 5, 2015 at 18:22 | comment | added | debabrata chakraborty | But what geometric estimate does those eigenvalues gives? | |
| Aug 5, 2015 at 18:15 | review | Close votes | |||
| Aug 6, 2015 at 7:25 | |||||
| Aug 5, 2015 at 17:59 | comment | added | Ryan Budney | There's a theorem that self-adjoint linear maps can be diagonalized via an orthogonal matrix. You can re-interpret this as a theorem about bilinear functions, that they can be diagonalized orthogonally. That gives you your interpretation. | |
| Aug 5, 2015 at 16:31 | history | asked | debabrata chakraborty | CC BY-SA 3.0 |