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Timeline for Average Multivariate Gaussian

Current License: CC BY-SA 3.0

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Aug 5, 2015 at 14:32 comment added Jean Duchon You're right, it's my bad understanding of "ever". I was about to give the same example. But with the conditions given here ($\mu\in[-1,1]$, unit variance) I bet the answer is no for $k=d=1$.
Aug 5, 2015 at 13:37 comment added Brendan McKay I think you missed the word "ever". Mixtures of gaussians are gaussian sometimes. For example, if u is gaussian then a mixture of gaussians with the same variance and mean u is gaussian.
Aug 5, 2015 at 13:23 history answered Jean Duchon CC BY-SA 3.0