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Nov 26, 2019 at 22:24 comment added Josiah Park @Rudi_Birnbaum It suffices to check that two closest vertices in a dodecahedron (inscribed in the sphere) are at a distance closer than $0.647046$, since one can give a spherical code with separation larger than this (see neilsloane.com/packings).
Dec 31, 2017 at 15:19 history edited Joseph O'Rourke CC BY-SA 3.0
Responding to a question.
Dec 31, 2017 at 9:29 comment added Raphael J.F. Berger $n=20$ is not a dodecahedron, why not and who solved that?
Apr 18, 2017 at 10:41 vote accept CPJ
Sep 8, 2015 at 12:41 history edited Joseph O'Rourke CC BY-SA 3.0
Update new result for n=10.
Jul 30, 2015 at 10:32 history edited Joseph O'Rourke CC BY-SA 3.0
Typo.
Jul 30, 2015 at 0:55 history edited Joseph O'Rourke CC BY-SA 3.0
Typo.
Jul 30, 2015 at 0:23 history edited Joseph O'Rourke CC BY-SA 3.0
Added Tammes problem history, as recounted by Musin & Tarasov.
Jul 29, 2015 at 23:11 comment added user21349 What's most surprising to me is that there is a link between a global property extrinsic to the surface (energy) and a local, intrinsic property (curvature).
Jul 29, 2015 at 21:19 comment added Joseph O'Rourke @BenCrowell: Nice! (McAllister, I. W. "Conductor curvature and surface charge density." Journal of Physics. D, Applied Physics 23.3 (1990): 359-362.) That anything interesting is the $4$-th root of the curvature is amazing.
Jul 29, 2015 at 20:54 history edited Joseph O'Rourke CC BY-SA 3.0
Minor clarification.
Jul 29, 2015 at 20:21 history edited Joseph O'Rourke CC BY-SA 3.0
Added a bit more detail.
Jul 29, 2015 at 19:25 comment added user21349 There is a problem similar to the Thompson problem, which is to find the minimum potential energy of a continuous charge distribution on a nonspherical conductor. There is a surprising set of exact solutions for some special shapes, in which the charge density is proportional to the fourth root of the absolute value of the Gaussian curvature. I W McAllister 1990 J. Phys. D: Appl. Phys. 23 359 doi:10.1088/0022-3727/23/3/016
Jul 29, 2015 at 12:18 history answered Joseph O'Rourke CC BY-SA 3.0