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Aug 18, 2015 at 21:17 comment added Piero D'Ancona You are right, I think that part of my answer is not useful (it leads to first order terms but with a special form). However you have the full formula in Andrew's answer, no? from that answer one might guess that the right transformation to use is $v(x,t)=u(x-bt,t)$
Aug 17, 2015 at 16:31 comment added foo90 I have tried your approach. For the zero order term it works, for the first order terms I haven't succeded, can you write something more?
Jul 27, 2015 at 20:57 comment added Piero D'Ancona Sorry, I have no reference for the higher order case. I guess it should be possible to do something along the lines of Hormander's computations
Jul 26, 2015 at 21:59 comment added foo90 Thank you. And for higher orde parabolic pde do you have some reference?
Jul 26, 2015 at 16:26 history answered Piero D'Ancona CC BY-SA 3.0