Timeline for If $f : [-a,a] \rightarrow \mathbb{IR}$ is Scott continuous, why are $f^-$ and $f^+$ measurable?
Current License: CC BY-SA 3.0
2 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Jul 25, 2015 at 12:09 | history | edited | Dominic van der Zypen | CC BY-SA 3.0 |
added 78 characters in body
|
Jul 25, 2015 at 11:37 | history | answered | Dominic van der Zypen | CC BY-SA 3.0 |