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Mar 12 at 23:11 history edited GH from MO
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Jul 22, 2015 at 19:15 comment added Greg Martin Another construction, that I suspect you will want to exclude, is to take an exponentially growing pan-periodic sequence (like $2^n$) and replace the $n$th term by its least nonnegative residue modulo the product of all the primes up to $\sqrt n$, say. This sequence grows slower than $(e+\epsilon)^{\sqrt n}$ and, modulo any fixed prime, is congruent to the original sequence after finitely many terms.
Jul 22, 2015 at 19:11 history edited Greg Martin CC BY-SA 3.0
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Jul 22, 2015 at 14:35 comment added Roland Bacher joro, thanks for your remark. You are right, I consider this to be trivial.
Jul 22, 2015 at 12:00 comment added joro Interleaving periodic sequences is again periodic. I suppose this is trivial for you: $a(2n)=poly_1(n),a(2n+1)=poly_2(n)$?
Jul 22, 2015 at 9:16 history edited Roland Bacher CC BY-SA 3.0
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Jul 22, 2015 at 8:59 history asked Roland Bacher CC BY-SA 3.0