Timeline for Is there a combinatorial interpretation of the identity $\sum_{k=0}^m 2^{-2k} \binom{2k}{k} \binom{2m-k}{m} =4^{-m} \binom{4m+1}{2m}$?
Current License: CC BY-SA 3.0
15 events
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| Oct 17, 2017 at 8:23 | history | edited | Wolfgang | CC BY-SA 3.0 |
put the identity in title, included link to paper
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| Apr 18, 2010 at 10:57 | answer | added | Sune Jakobsen | timeline score: 6 | |
| Apr 15, 2010 at 2:37 | comment | added | Aeryk | You might want to check out "Proofs that Really Count" by Art Benjamin. It has a bunch of combinatorial proofs of identities and one whole chapter is on binomial coefficient identities. I don't know if this one is in there, but it might be a good place to look for general insight. | |
| Apr 14, 2010 at 18:02 | answer | added | Jason Dyer | timeline score: 2 | |
| Apr 14, 2010 at 0:59 | comment | added | Sunni | @Nate: jc have told you that. | |
| Apr 13, 2010 at 22:24 | comment | added | j.c. | @Nate: I bet it's this one: dx.doi.org/10.1016/j.exmath.2009.02.005 "A remarkable sequence of integers" by Victor H. Moll and Dante V. Manna. Expositiones Mathematicae Volume 27, Issue 4, 2009, Pages 289-312 | |
| Apr 13, 2010 at 21:16 | comment | added | Nate Eldredge | Could you give the full reference to the paper where you found it? | |
| Apr 13, 2010 at 16:43 | history | edited | Reid Barton | CC BY-SA 2.5 |
edited title
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| Apr 13, 2010 at 15:15 | history | edited | Sunni | CC BY-SA 2.5 |
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| Apr 13, 2010 at 14:52 | history | edited | Andrew Stacey | CC BY-SA 2.5 |
Added 'aligned' to displayed maths to (hopefully) make it clearer.
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| Apr 13, 2010 at 14:33 | history | edited | David E Speyer | CC BY-SA 2.5 |
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| Apr 13, 2010 at 14:28 | history | edited | David E Speyer | CC BY-SA 2.5 |
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| Apr 13, 2010 at 14:22 | history | edited | David E Speyer | CC BY-SA 2.5 |
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| Apr 13, 2010 at 14:14 | history | edited | David E Speyer | CC BY-SA 2.5 |
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| Apr 13, 2010 at 13:34 | history | asked | Sunni | CC BY-SA 2.5 |