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Oct 13, 2016 at 0:02 vote accept Brian Ding
Oct 13, 2016 at 0:02 vote accept Brian Ding
Oct 13, 2016 at 0:02
Oct 13, 2016 at 0:01 vote accept Brian Ding
Oct 13, 2016 at 0:02
Oct 12, 2016 at 18:47 comment added Dan Fox See Theorems 2.4.2 and 2.4.4 of the book Interior-point Polynomial Algorithms in Convex Programming of Nesterov and Nemirovskii.
Jul 24, 2015 at 14:48 answer added funda timeline score: 2
Jul 21, 2015 at 19:58 history edited Brian Ding CC BY-SA 3.0
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Jul 21, 2015 at 18:11 comment added Brian Ding @Suvrit, that would be very nice. So far what I found is that $f^*$ is also self-concordant but I don't know the domain of it. See stanford.edu/~boyd/cvxbook/bv_cvxbook.pdf,pp517,exercise 9.20.
Jul 21, 2015 at 11:53 comment added Suvrit I think if $f$ is self-concordant for $K$, then barring some pathology, its Legendre transform $f^*$ should be self-concordant for $K^\circ$ (notice, polar cone not dual-cone)....this sounds like a textbook result.
Jul 21, 2015 at 5:02 history asked Brian Ding CC BY-SA 3.0