Timeline for Permutable (Lie) subgroups
Current License: CC BY-SA 3.0
6 events
when toggle format | what | by | license | comment | |
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Jul 20, 2015 at 16:17 | comment | added | Duchamp Gérard H. E. | @JoséFigueora Yes, the key point was of course (I say "of course" after interaction however) Sard's theorem which here says that "somewhere" the action is a submersion. And the situation is the same everywhere due to the transitivity of the action of $A\times B$ | |
Jul 20, 2015 at 7:23 | history | undeleted | José Figueroa-O'Farrill | ||
Jul 20, 2015 at 7:23 | history | edited | José Figueroa-O'Farrill | CC BY-SA 3.0 |
corrected an error in the proof.
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Jul 19, 2015 at 22:52 | history | deleted | José Figueroa-O'Farrill | via Vote | |
Jul 19, 2015 at 22:32 | comment | added | Duchamp Gérard H. E. | Of course, all this is straightforward once one knows that the multiplication $$A\times B\rightarrow G$$ is a submersion ... which is exactly what I need. | |
Jul 19, 2015 at 17:33 | history | answered | José Figueroa-O'Farrill | CC BY-SA 3.0 |