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Timeline for Permutable (Lie) subgroups

Current License: CC BY-SA 3.0

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Jul 20, 2015 at 16:17 comment added Duchamp Gérard H. E. @JoséFigueora Yes, the key point was of course (I say "of course" after interaction however) Sard's theorem which here says that "somewhere" the action is a submersion. And the situation is the same everywhere due to the transitivity of the action of $A\times B$
Jul 20, 2015 at 7:23 history undeleted José Figueroa-O'Farrill
Jul 20, 2015 at 7:23 history edited José Figueroa-O'Farrill CC BY-SA 3.0
corrected an error in the proof.
Jul 19, 2015 at 22:52 history deleted José Figueroa-O'Farrill via Vote
Jul 19, 2015 at 22:32 comment added Duchamp Gérard H. E. Of course, all this is straightforward once one knows that the multiplication $$A\times B\rightarrow G$$ is a submersion ... which is exactly what I need.
Jul 19, 2015 at 17:33 history answered José Figueroa-O'Farrill CC BY-SA 3.0