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Jul 19, 2015 at 4:26 vote accept José Figueroa-O'Farrill
Jul 19, 2015 at 0:41 comment added Daniele Sepe With pleasure, @JoséFigueroa-O'Farrill! I have included an answer to the question below, but I am sure that you have already worked it out :)
Jul 19, 2015 at 0:39 answer added Daniele Sepe timeline score: 9
Jul 19, 2015 at 0:10 comment added José Figueroa-O'Farrill Thank you, @Daniele! I didn't know this paper and it is very useful.
Jul 18, 2015 at 23:02 comment added José Figueroa-O'Farrill @DanieleSepe: Hi! Indeed, I have a Jacobi structure on a nontrivial line bundle, but I thought that I had more that that, since I have also the map from sections to vector fields, which is why I thought at first that I would have a Lie algebroid.
Jul 18, 2015 at 22:16 comment added Daniele Sepe Hi José, another possibly silly question: is your bracket local? That is, does $supp [e_1,e_2] \subset supp \, e_1 \cap supp \, e_2$ hold, where $supp$ denotes the support and $e_1,e_2 \in \Gamma(E)$ are (possibly locally defined) sections? I suspect that the answer to the above question is yes; in which case, you are in the presence of a Jacobi structure (I can write a longer answer with some references if that is the case).
Jul 18, 2015 at 15:22 history edited José Figueroa-O'Farrill CC BY-SA 3.0
added some additional information to illustrate that this is far from generic.
Jul 17, 2015 at 3:55 comment added José Figueroa-O'Farrill Not a silly question and perhaps I should have mentioned it. I find that $$\rho(f e)(g) - f \rho(e)(g) = T_e(df,dg),$$ where $T_e$ is a bivector.
Jul 17, 2015 at 3:21 comment added David Roberts Silly question: How far from being $C^\infty(M)$-linear is $\rho$?
Jul 17, 2015 at 2:53 history asked José Figueroa-O'Farrill CC BY-SA 3.0