Timeline for Solving $\lambda U^{\dagger}V -\bar{\lambda} V^{\dagger}U = A$
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 17, 2015 at 0:09 | comment | added | Benjamin | Actually $V \mapsto UV$ does the job if $U$ is given and $V$ is your $V$ from your answer. | |
| Jul 17, 2015 at 0:06 | comment | added | Benjamin | and $\lambda$ I should have said. | |
| Jul 16, 2015 at 23:54 | comment | added | Benjamin | That's great thanks! Will this still be possible is $U$ is also given? I.e. given $A$ and $U$ can we always solve for $V$? | |
| Jul 16, 2015 at 22:43 | history | answered | loup blanc | CC BY-SA 3.0 |