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Jul 17, 2015 at 19:53 vote accept Nikola Kovachki
Jul 17, 2015 at 19:53 comment added Nikola Kovachki Thanks! I actually should have seen this earlier, but since $H$ is full rank and $C$ is the null space of $H$, it's immediate that $|C|=2^n$. Nevertheless, your approach is really nice because if you Taylor expand $A(x,y)$ around $x=0$ then you get $A(x,y) = 1+x(y^2+1)+x^2(2y^3+y^2+1)+...$ and that exactly determines the coefficients $a(n,k)$, so, if I can get a closed form of that expansion, I'll have an exact answer. Do you mind elaborating a bit on how you obtained your recurrence relations as it is not obvious to me.
Jul 16, 2015 at 5:24 history answered Gjergji Zaimi CC BY-SA 3.0