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Timeline for Generalized geometries

Current License: CC BY-SA 3.0

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Jul 16, 2015 at 17:06 comment added Will Sawin @Guntram let me modify the odd-numbered steps to, if no elements would otherwise be added, add one element and not put it in no sets.
Jul 16, 2015 at 15:47 comment added Guntram This does not work for $n=1$ as the resulting set is finite. For other $n$ it also needs to be shown that this process does not terminate.
Jul 16, 2015 at 13:16 vote accept Dominic van der Zypen
Jul 16, 2015 at 12:57 comment added Will Sawin @DominicvanderZypen Every $n$-tuple of elements of $S$ appears in one of the odd numbered step, when the last element appears. Then unless it's already contained in an element of $\mathfrak B$, by the next even numbered step it enters $\mathfrak B$, and it stays contained in an element of $\mathfrak B$ for each subsequence step. Similarly, every pair of elements of $\mathfrak B$ appears at some point, and then the intersection becomes $n-1$, and then it doesn't go down or up.
Jul 16, 2015 at 6:55 comment added Dominic van der Zypen Thanks for these ideas! It looks like they work, but I'm still a little uneasy about the statement "So both are satisfied in the limit." Can you elaborate on this a little bit? (Sorry for not accepting your answer yet; I will do it once I understand the limit part.)
Jul 16, 2015 at 2:07 history answered Will Sawin CC BY-SA 3.0