Timeline for Simplifying an expression using tools from Fourier transform
Current License: CC BY-SA 3.0
10 events
when toggle format | what | by | license | comment | |
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Jul 17, 2015 at 6:48 | vote | accept | Jeff | ||
Jul 16, 2015 at 23:12 | comment | added | Jeff | solved, you are right. there is no contradiction. | |
Jul 16, 2015 at 20:15 | comment | added | Carlo Beenakker | try $\gamma=3$ or $\gamma=4$, where the integral can be done exactly for finite $R$; then take the limit $R\rightarrow\infty$ and you get 1/2, what contradiction might there be? | |
Jul 16, 2015 at 19:23 | history | edited | Carlo Beenakker | CC BY-SA 3.0 |
added 202 characters in body
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Jul 16, 2015 at 15:32 | comment | added | Jeff | There is a contradiction with this proof. I posed a question to highlight this contradiction. You may see math.stackexchange.com/questions/1363393/… and let me know your comments. | |
Jul 16, 2015 at 12:55 | review | Suggested edits | |||
Jul 16, 2015 at 12:59 | |||||
Jul 15, 2015 at 17:50 | history | edited | Carlo Beenakker | CC BY-SA 3.0 |
added 487 characters in body
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Jul 15, 2015 at 17:44 | history | undeleted | Carlo Beenakker | ||
Jul 15, 2015 at 17:42 | history | deleted | Carlo Beenakker | via Vote | |
Jul 15, 2015 at 17:39 | history | answered | Carlo Beenakker | CC BY-SA 3.0 |