Skip to main content
10 events
when toggle format what by license comment
Jun 30, 2019 at 15:54 comment added Tim Campion For my own sanity: under GCH, what we conclude is that $|P|$ is uncountable, and is either a limit cardinal or the successor of a limit cardinal.
Jul 16, 2015 at 11:06 history edited Keith Kearnes CC BY-SA 3.0
added 20 characters in body
Jul 16, 2015 at 7:29 vote accept student9909
Jul 15, 2015 at 21:28 comment added Joseph Van Name I must also mention that if $\mu$ is the strong limit cardinal with $\mu\leq|P|\leq 2^{\mu}$, then $\mu$ is not a weakly compact cardinal since if $\mu\rightarrow(\mu)^{2}_{3}$, then $|P|$ would have a well-ordered or anti-well ordered chain or an antichain of cardinality $\mu$ which is a contradiction.
Jul 15, 2015 at 9:05 history edited Keith Kearnes CC BY-SA 3.0
added 2 characters in body
Jul 14, 2015 at 19:17 history edited Keith Kearnes CC BY-SA 3.0
added 540 characters in body
Jul 14, 2015 at 15:35 history edited Keith Kearnes CC BY-SA 3.0
added 651 characters in body
Jul 14, 2015 at 14:36 history edited Keith Kearnes CC BY-SA 3.0
added 19 characters in body
Jul 14, 2015 at 13:45 history edited Keith Kearnes CC BY-SA 3.0
added 136 characters in body
Jul 14, 2015 at 13:30 history answered Keith Kearnes CC BY-SA 3.0