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Apr 13, 2010 at 4:58 history edited abcdxyz CC BY-SA 2.5
added 235 characters in body
Apr 13, 2010 at 2:19 vote accept abcdxyz
Apr 13, 2010 at 1:53 comment added abcdxyz The problem that I found (if it is really a problem) is that there might be no element in the neighborhood of $a$ which has of norm 1. I try to mimic the original proof for the cyclic case but the independence of automorphism does not work anymore, I mean it still work but I can not bound the $b$ given by this process.
Apr 12, 2010 at 20:57 answer added Paul Broussous timeline score: 8
Apr 12, 2010 at 19:35 comment added Felipe Voloch Doesn't that follow from the standard proof?
Apr 12, 2010 at 19:14 history edited abcdxyz CC BY-SA 2.5
edited body
Apr 12, 2010 at 19:14 comment added abcdxyz the error is fixed.
Apr 12, 2010 at 18:26 comment added James Weigandt I think you want $L$ a finite cyclic extension of $K$, not of $L$.
Apr 12, 2010 at 18:18 history asked abcdxyz CC BY-SA 2.5