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Feb 25, 2022 at 15:11 history edited coudy CC BY-SA 4.0
correct spelling
Jul 16, 2015 at 11:58 vote accept Anna maredric
Jul 5, 2015 at 2:47 answer added Apue timeline score: 1
Jul 4, 2015 at 17:59 history edited YCor
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Jul 4, 2015 at 12:34 answer added Ofir Gorodetsky timeline score: 4
Jul 4, 2015 at 11:58 comment added Ofir Gorodetsky By Jensen, this is immediate for convex $f$: $\sum x_i f(x_i) = K \sum \frac{x_i}{K} f(x_i) \ge K f(\sum x_i^2 / K)$, and since $f$ is monotone increasing and by C-S $\sum x_i^2 / K \ge (\sum x_i)^2 /(nK) = K/n$, we're done.
Jul 4, 2015 at 11:46 review First posts
Jul 4, 2015 at 11:56
Jul 4, 2015 at 11:43 history asked Anna maredric CC BY-SA 3.0