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Jul 1, 2015 at 17:44 comment added user115940 Thanks Mohan. What if $A$ and $B$ are both assumed to be smooth? This is actually the case.
Jul 1, 2015 at 15:50 comment added Mohan If you only move $A$, this is impossible. For example, take $X$ to be a projective space, $A$ a hypersurface and $B$ to be a subvariety with positive dimensional singular locus. Whatever $A$ is moved to, it is still a hypersurface and will meet $B$ in some singular points.
Jul 1, 2015 at 14:32 comment added Jason Starr Hmm, actually my last suggestion won't work. The determinantal locus can be made smooth away from the locus where the $\mathcal{O}_A$-module homomorphism drops rank (further). However, it will typically be singular on that locus.
Jul 1, 2015 at 14:17 comment added Jason Starr This would be simpler if you allowed to replace $A$ by $N\cdot A$ for $N$ a sufficiently positive and divisible integer. Use the isomorphism of $K$-theory and Chow theory, i.e., write $A$ as a polynomial in Chern classes $c_r$ of locally free sheaves $\mathcal{E}$. Using finite differences, $c_r(\mathcal{E})$ can be expressed in terms of Chern classes of $\mathcal{E}(d)$ for $d$ large. Thus, you need only find global sections of $\mathcal{E}(d)|_B$ whose determinantal locus is transversal (i.e., a Bertini-type theorem). Finally, extend those to global sections of $\mathcal{E}(d)$.
Jul 1, 2015 at 9:33 review First posts
Jul 1, 2015 at 9:42
Jul 1, 2015 at 9:19 history asked user115940 CC BY-SA 3.0