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Timeline for Does projective imply flat?

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Jul 1, 2015 at 0:23 vote accept Theo Johnson-Freyd
Jun 30, 2015 at 22:15 comment added Theo Johnson-Freyd @EricWofsey Ah, good point.
Jun 30, 2015 at 22:14 comment added Eric Wofsey @TheoJohnson-Freyd: A projective non-flat object can never have a flat resolution, since by projectivity the first map in the resolution will split and a direct summand of a flat object is flat.
Jun 30, 2015 at 22:06 comment added Theo Johnson-Freyd Well, grumble. And this gives an example where I don't even have flat resolutions, since by the same logic $(N,1)$ fails to be flat for every $N$. (Tensoring with $(M,0)$ and then projecting onto the $\mathcal B$ factor still gives the functor $F$.)
Jun 30, 2015 at 21:10 comment added thel yeah, book-keeping problem on my side, sorry. Both ways work.
Jun 30, 2015 at 21:06 history edited Eric Wofsey CC BY-SA 3.0
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Jun 30, 2015 at 21:01 comment added Eric Wofsey @ThelSeraphim: I don't see how the $V\otimes W$ term causes any trouble; it is natural to include it in the special case described in the penultimate paragraph. I think you're right that the "square-zero" version without it also works, though.
Jun 30, 2015 at 20:46 comment added thel I think your $V \otimes W$ factor may be spurious? Doesn't it spoil associativity? I'm pretty sure the square-zero extension version of what you're saying works. Beautiful example.
Jun 30, 2015 at 20:34 history edited Eric Wofsey CC BY-SA 3.0
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Jun 30, 2015 at 20:21 history edited Eric Wofsey CC BY-SA 3.0
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Jun 30, 2015 at 19:38 history edited Eric Wofsey CC BY-SA 3.0
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Jun 30, 2015 at 19:07 history answered Eric Wofsey CC BY-SA 3.0