Timeline for What is the exterior derivative intuitively?
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
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| Nov 23, 2019 at 1:58 | comment | added | Vectornaut | @timur: Thanks so much! Reading the original seems much less daunting now that I can see how the relevant lectures are organized. One of these days I'll pull out my dictionary and have a go at it. | |
| Nov 18, 2019 at 1:21 | comment | added | timur | @Vectornaut: It is in Lecture 9. The $\delta$ is defined in Lecture 8. | |
| S Mar 26, 2019 at 15:41 | history | suggested | MaudPieTheRocktorate | CC BY-SA 4.0 |
fixed the symbol. That paragraph is supposed to define $L_k(M)$.
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| Mar 26, 2019 at 15:28 | review | Suggested edits | |||
| S Mar 26, 2019 at 15:41 | |||||
| S Mar 26, 2019 at 14:56 | history | suggested | MaudPieTheRocktorate | CC BY-SA 4.0 |
fixed a formula of $f$, and clarified that $f$ must be real.
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| Mar 26, 2019 at 12:31 | review | Suggested edits | |||
| S Mar 26, 2019 at 14:56 | |||||
| Nov 17, 2017 at 21:34 | comment | added | Vectornaut | I'd really like to read more about this approach, but unfortunately I can't read Russian. Do you happen to know of a reference in English, Spanish, or (as a last resort) some other Romance language? The closest thing I've found is Anders Kock's writing on synthetic differential geometry (for example, Section I.18 of Synthetic Differential Geometry), but it carries a lot of very general baggage; I just want to learn about plain old smooth manifolds. (As a very last resort, could you point me to where in Feigin's lectures this stuff can be found?) | |
| Jan 19, 2016 at 15:19 | comment | added | LSpice | At the end of your third paragraph, should $I(t) = \mathrm o(t^k)$ be $f(I(t)) = \mathrm o(t^k)$? | |
| Apr 12, 2010 at 16:39 | comment | added | Qfwfq | This seems to me analogous to the way algebraic geometers define $\Omega^{1}$ as $\mathcal{I}_\Delta/\mathcal{I}_\Delta^{2}$, where $\mathcal{I}_\Delta$ is the ideal sheaf of the diagonal. | |
| Apr 12, 2010 at 2:46 | comment | added | Vectornaut | This is cool! Am I right in thinking that you can identify the set of k-vectors on M with the set of derivations on S_k, just as you can identify the set of 1-vectors on M with the set of derivations on S_1? | |
| Apr 11, 2010 at 22:51 | history | answered | Petya | CC BY-SA 2.5 |