Timeline for A curious determinantal inequality
Current License: CC BY-SA 3.0
12 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Feb 5, 2017 at 11:33 | history | edited | M. Lin | CC BY-SA 3.0 |
an update added.
|
Jul 4, 2015 at 12:39 | answer | added | Suvrit | timeline score: 5 | |
Jun 28, 2015 at 2:24 | vote | accept | M. Lin | ||
Jun 28, 2015 at 1:17 | answer | added | Terry Tao | timeline score: 29 | |
Jun 27, 2015 at 20:26 | comment | added | M. Lin | @GerhardPaseman: I think there would be lots of similar inequalities. The one I am asking may be the "simplest" unknown case. | |
Jun 27, 2015 at 17:57 | comment | added | Gerhard Paseman | Perhaps it is easier if we remove square roots? Rewriting, I get det(A^4 + ABBA + BAAB + B^4) >= det(A^4 +AABB + BBAA + B^4). While temptingly pleasing, I don't know if positive definite is enough of a restriction to carry this through. Are there similar ineqaulities which are true and motivating? Gerhard "Don't Know About Hermitian Matrices" Paseman, 2015.06.27 | |
Jun 27, 2015 at 4:36 | answer | added | Terry Tao | timeline score: 9 | |
Jun 27, 2015 at 4:05 | comment | added | Russel | Equality occurs if A B commute. | |
Jun 27, 2015 at 4:03 | comment | added | The Masked Avenger | Notice equality occurs if A=I. Can you rewrite (A+B) as A(I + A^(-1)B) and find appropriate square roots of A^-1 B ? | |
Jun 26, 2015 at 21:02 | comment | added | GH from MO | @Moritz: It doesn't matter since $\det(X)^2=\det(X^2)$. | |
Jun 26, 2015 at 20:59 | comment | added | Moritz | Does it read $(\det(A+B))^2$ or $\det((A+B)^2)$? | |
Jun 26, 2015 at 20:27 | history | asked | M. Lin | CC BY-SA 3.0 |