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Oct 28, 2022 at 5:02 review Close votes
Nov 2, 2022 at 3:01
Oct 3, 2010 at 3:56 answer added Sándor Kovács timeline score: 2
Jul 1, 2010 at 13:59 vote accept Amira
Jun 25, 2010 at 5:31 answer added Richard Montgomery timeline score: 2
Apr 12, 2010 at 2:53 comment added Karl Schwede Alternately, if $\pi$ is \e'tale in codimension 1, then you can show that $Y$ has rational singularities.
Apr 11, 2010 at 18:30 comment added Torsten Ekedahl I think you may be thinking of the case of a finite morphism $\pi\colon X \to Y$ where $X$ is smooth. In that case the singularities of $Y$ are indeed quotient singularities. Not necessarily cyclic quotient singularities however; an $E_8$-singularity for instance is the quotient of $\mathbb C^2$ by the icosahedral group which is not cyclic.
Apr 11, 2010 at 16:02 comment added VA. This is still a nonsense question. Take $Y$ = the cone over an elliptic curve, and $f:Y\to X$ a projection to $Y=\mathbb P^2$. $Y$ is normal, the singularity is not cyclic quotient.
Apr 11, 2010 at 15:48 history edited Amira CC BY-SA 2.5
I changed the set-up a bit. It was too general and I emphasized my motivation.; deleted 1 characters in body
Apr 11, 2010 at 15:44 comment added Amira Ok. My question is too general. I edited it. (I'm really confused here.) Could somebody maybe give a reference to where all this material on "singularity types" is written down carefully? I'd like to understand how to show that cyclic quotient singularities are rational in my case.
Apr 11, 2010 at 14:44 comment added Charles Siegel @Torsten: My thought is that Amira has something crossed from the ADE singularities. Not familiar enough with the general theory though to be sure of what.
Apr 11, 2010 at 14:29 comment added Torsten Ekedahl There are many more normal surface singularities than cyclic quotient singularities or for that matter rational singularities (which is defined by the condition of the second paragraph). You must have misinterpreted something. To take just one example: The cone point of the affine cone of an elliptic curve (embedded in the projective plane say) is not a rational singularity.
Apr 11, 2010 at 14:16 history asked Amira CC BY-SA 2.5