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Is there any polynomial $f(x,y)\in{\mathbb Q}[x,y]{}\ $$f(x,y)\in{\mathbb Q}[x,y]{}$ such that $f:\mathbb{Q}\times\mathbb{Q} \rightarrow\mathbb{Q}$$f\colon\mathbb{Q}\times\mathbb{Q} \rightarrow\mathbb{Q}$ is a bijection?

Is there any polynomial $f(x,y)\in{\mathbb Q}[x,y]{}\ $ such that $f:\mathbb{Q}\times\mathbb{Q} \rightarrow\mathbb{Q}$ is a bijection?

Is there any polynomial $f(x,y)\in{\mathbb Q}[x,y]{}$ such that $f\colon\mathbb{Q}\times\mathbb{Q} \rightarrow\mathbb{Q}$ is a bijection?

Question Protected by Andrés E. Caicedo

Polynomial bijection from QxQ$\mathbb Q\times\mathbb Q$ to Q$\mathbb Q$?

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Andrés E. Caicedo
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Is there any polynomial $f(x,y)\in\mathbb{Q}[x,y]$$f(x,y)\in{\mathbb Q}[x,y]{}\ $ such that $f:\mathbb{Q}\times\mathbb{Q} \rightarrow\mathbb{Q}$ is a bijection?

Is there any polynomial $f(x,y)\in\mathbb{Q}[x,y]$ such that $f:\mathbb{Q}\times\mathbb{Q} \rightarrow\mathbb{Q}$ is a bijection?

Is there any polynomial $f(x,y)\in{\mathbb Q}[x,y]{}\ $ such that $f:\mathbb{Q}\times\mathbb{Q} \rightarrow\mathbb{Q}$ is a bijection?

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Greg Kuperberg
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Z.H.
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