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Jun 24, 2015 at 11:11 comment added Sebastian Schoennenbeck Thank you for your comments, they were very helpful. I came across the construction via the quaternions earlier but was somehow thrown off the tracks by a a confusing remark.
Jun 24, 2015 at 11:08 vote accept Sebastian Schoennenbeck
Jun 24, 2015 at 4:18 comment added Mikhail Borovoi @YCor: Moreover, any $\mathbb{Q}$-form of ${\rm Sp}_{2m}$ splits at almost all primes $p$ (because it is an inner form of a split $\mathbb{Q}$-group).
Jun 24, 2015 at 4:10 comment added Mikhail Borovoi I guess that the standard quaternion algebra $H=\mathbb{Q}(i,j)$ with $i^2=-1,\ j^2=-1,\ ji=-ij$ ramifies exactly at $\infty$ and 2. It follows that the unitary group $G=SU(H^n,F)$ of the hermitian form $F(x)=x_1 \bar{x}_1+\dots+x_n\bar{x}_n$ from YCor's first comment splits at every prime $p$ except $\infty$ and maybe at $p=2$. It does not split at 2 because it cannot be nonsplit at one place only by the reciprocity law (I mean the Hasse-Brauer-Noether theorem).
Jun 23, 2015 at 21:38 comment added YCor PS: I guess that a semisimple group over $\mathbf{Q}$ will be automatically be split over $\mathbf{Q}_p$ for $p$ ranging over a positive density set of primes.
Jun 23, 2015 at 14:38 answer added grghxy timeline score: 7
Jun 23, 2015 at 14:02 comment added YCor All simply connected semisimple real algebraic groups are definable over the rationals. Here the simplest is just the stabilizer of the standard positive definite hermitian form on the $H^n$ where $H$ are the usual quaternions (with the standard basis).
Jun 23, 2015 at 13:40 history asked Sebastian Schoennenbeck CC BY-SA 3.0