Timeline for What is the $\mathbb Z/2$-cohomology of $\mathrm B^n(\mathbb Z/2)$?
Current License: CC BY-SA 3.0
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| Jun 15, 2020 at 7:27 | history | edited | CommunityBot |
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| Jun 21, 2015 at 19:23 | comment | added | Prasit | @EricWofsey Good point. Thanks for pointing it out. | |
| Jun 21, 2015 at 19:21 | history | edited | Prasit | CC BY-SA 3.0 |
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| Jun 21, 2015 at 16:44 | comment | added | Eric Wofsey | It should be mentioned that the algebra structure on the Steenrod algebra is not the colimit of the algebra structure coming from the cup product. Rather, it comes from thinking of these cohomology classes as operations on cohomology and composing them. In fact, the cup product does not commute with the maps making up the colimit (which are induced by suspension), and so cannot even be defined in the limit. | |
| Jun 21, 2015 at 15:22 | history | edited | Prasit | CC BY-SA 3.0 |
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| Jun 21, 2015 at 12:39 | history | answered | Prasit | CC BY-SA 3.0 |