Timeline for Spectral radius of a rank-1 perturbation
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| Jun 9, 2023 at 13:03 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| May 10, 2023 at 13:05 | comment | added | Rodrigo de Azevedo | @AlexanderMathiasen I assume it's using the spectral norm as an upper bound. Take a look at the answer I just posted. | |
| May 10, 2023 at 13:03 | answer | added | Rodrigo de Azevedo | timeline score: 1 | |
| May 10, 2023 at 12:35 | answer | added | Rodrigo de Azevedo | timeline score: 0 | |
| May 10, 2023 at 11:53 | history | edited | Rodrigo de Azevedo | CC BY-SA 4.0 |
added 148 characters in body; edited tags
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| Aug 28, 2020 at 13:49 | comment | added | Alexander Mathiasen | I'm not sure I understand why $r\le ||A||+||u||||v||$. | |
| Jun 20, 2015 at 18:39 | comment | added | user47305 | Thanks! That's basically my impression too, but figured it was worth a shot. | |
| Jun 20, 2015 at 18:28 | comment | added | Christian Remling | A trivial bound is $r\le \|A\|+\|u\|\, \|v\|$, and I doubt that much more can be said in general. In particular, it's definitely not possible to bound $r(A+uv^t)$ in terms $r(A)$ and $\|u\|$, $\|v\|$, as simple examples show. | |
| Jun 20, 2015 at 18:18 | history | asked | user47305 | CC BY-SA 3.0 |