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Jun 19, 2015 at 16:31 comment added Salvo Tringali Yes, and I was thinking of cancelling the post after having discussed the question with Alain Plagne. Should I? I see now the idea I had in mind can't work in any case.
Jun 19, 2015 at 16:30 comment added Eric Naslund Perhaps I am not understanding the question, but isn't the set $$A=\{n\lfloor\log^{[k]}(n)\rfloor : \ n\in\mathbb{N}\}$$ a counterexample for any $k$?
Jun 19, 2015 at 15:23 history edited Salvo Tringali CC BY-SA 3.0
Fixed typo in the title
Jun 19, 2015 at 15:00 history edited Salvo Tringali CC BY-SA 3.0
Removed a useless assumption
Jun 19, 2015 at 14:50 history edited Salvo Tringali CC BY-SA 3.0
added 19 characters in body
Jun 19, 2015 at 14:45 history asked Salvo Tringali CC BY-SA 3.0