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Jun 25, 2015 at 13:09 vote accept Uche Opara
Jun 21, 2015 at 16:11 comment added Holonomia If your complete Riemannian manifold is an irreducible symmetric space then it has a totally geodesic hypersurface iff is a space form. This is an old result. For a nice recent proof see Theorem 5.5. arxiv.org/pdf/1401.3585.pdf
Jun 21, 2015 at 2:05 history edited Robert Bryant
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Jun 19, 2015 at 14:29 answer added Robert Bryant timeline score: 23
Jun 18, 2015 at 11:24 history asked Uche Opara CC BY-SA 3.0