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Apr 19, 2019 at 13:59 answer added Denis Serre timeline score: 1
S Apr 19, 2019 at 12:54 history suggested Skeeve CC BY-SA 4.0
corrected a typo in the notation of Sobolev space (and some other typos)
Apr 19, 2019 at 11:50 review Suggested edits
S Apr 19, 2019 at 12:54
Apr 19, 2019 at 11:33 history edited Carlo Beenakker CC BY-SA 4.0
title , no stupid question
Apr 19, 2019 at 11:05 answer added Kweku A timeline score: 2
Jul 18, 2015 at 16:45 comment added Johannes Hahn You could just use $C^\infty(\mathbb{R}^n)$ oder $C_c^\infty(\mathbb{R}^n)$ as a test function space.
Jul 18, 2015 at 16:27 answer added BLM timeline score: -1
Jun 21, 2015 at 3:05 review Close votes
Jun 21, 2015 at 9:09
Jun 17, 2015 at 10:20 comment added mediocre Thank you very much for your comments. You are right indeed that if we choose this particular space, the Neumann derivative shall be zero, but can we choose any other testing space instead which might legitimize the definition?
Jun 16, 2015 at 10:58 review Close votes
Jun 16, 2015 at 12:28
Jun 16, 2015 at 10:29 comment added Michael Renardy The problem is that if you pick $f\in H_0^{s+2}$, then $\partial f/\partial\nu$ will be zero on the boundary.
S Jun 16, 2015 at 5:00 history suggested Duchamp Gérard H. E. CC BY-SA 3.0
Corrected spelling of the name Sobolev
Jun 16, 2015 at 4:52 review Suggested edits
S Jun 16, 2015 at 5:00
Jun 16, 2015 at 4:37 history edited mediocre
edited tags
Jun 16, 2015 at 4:31 review First posts
Jun 16, 2015 at 5:09
Jun 16, 2015 at 4:31 history asked mediocre CC BY-SA 3.0