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Ricardo Andrade
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Given $n$ and $t$ lengths $ l_i, 1\leq l_1<l_2<\cdots<l_t\leq n-1$, of directed diagonals within an $n$-gon such that $l_1+\cdots+l_t\neq 0 \pmod n)$. Does it exist a directed path within the n-gon using each of the given lengths exactly once (and no vertex twice)?

Here the length of a directed diagonal within any kind of an n-gon is the number of sides of the n-gon between the starting and the end vertex counted in a fixed direction. A directed path is a sequence $(d_1,d_2,\ldots,d_t)$ of directed diagonals such that the end vertex of $d_i$ is the starting vertex of $d_{i+1}$ for $i=1,2,…,t-1$.

In number theory, it is equivalent to: For any subset $S=\{l_1,\ldots,l_t\}$ of $\{1,2,…,n-1\}$ with $ l_i, 1\leq l_1<l_2<\cdots<l_t\leq n-1$ and $l_1+\cdots+l_t\neq 0 \pmod n$. Is there any a permutation of the elements of the subset $S$ such that no set of consecutive elements in this permutation has sum $=0 \pmod n$. Can anyone give me a counter-example or prove it?

In Graph theory, I can rephrase this question to: Let $\mathbb{Z}_n$ be a group of integers modulo $n$ and $S=\{l_1,\dots,l_t\}$ be a set of positive integers such that $1\le l_1<l_2< \dots < l_t \le n-1$, where $l_1+\dots + l_t \not\equiv 0 \pmod n$).

Let $P_t$ be a directed path of length $t$ ($t+1$ vertices). Can you label the vertices of the directed path $\overrightarrow{P_t}$ of length $t$ with distinct elements of $\mathbb{Z}_n$ such that the label differences on edges are exactly $S$? The difference is taking by subtract the head by the tail (then take mod $n$).

I have a proof for case $t\leq 6$. However, I wonder is it true or not in general. Many thanks.

Given $n$ and $t$ lengths $ l_i, 1\leq l_1<l_2<\cdots<l_t\leq n-1$, of directed diagonals within an $n$-gon such that $l_1+\cdots+l_t\neq 0 \pmod n)$. Does it exist a directed path within the n-gon using each of the given lengths exactly once (and no vertex twice)?

Here the length of a directed diagonal within any kind of an n-gon is the number of sides of the n-gon between the starting and the end vertex counted in a fixed direction. A directed path is a sequence $(d_1,d_2,\ldots,d_t)$ of directed diagonals such that the end vertex of $d_i$ is the starting vertex of $d_{i+1}$ for $i=1,2,…,t-1$.

In number theory, it is equivalent to: For any subset $S=\{l_1,\ldots,l_t\}$ of $\{1,2,…,n-1\}$ with $ l_i, 1\leq l_1<l_2<\cdots<l_t\leq n-1$ and $l_1+\cdots+l_t\neq 0 \pmod n$. Is there any a permutation of the elements of the subset $S$ such that no set of consecutive elements in this permutation has sum $=0 \pmod n$. Can anyone give me a counter-example or prove it?

In Graph theory, I can rephrase this question to: Let $\mathbb{Z}_n$ be a group of integers modulo $n$ and $S=\{l_1,\dots,l_t\}$ be a set of positive integers such that $1\le l_1<l_2< \dots < l_t \le n-1$, where $l_1+\dots + l_t \not\equiv 0 \pmod n$).

Let $P_t$ be a directed path of length $t$ ($t+1$ vertices). Can you label the vertices of the directed path $\overrightarrow{P_t}$ of length $t$ with distinct elements of $\mathbb{Z}_n$ such that the label differences on edges are exactly $S$? The difference is taking by subtract the head by the tail (then take mod $n$).

I have a proof for case $t\leq 6$. However, I wonder is it true or not in general. Many thanks

Given $n$ and $t$ lengths $ l_i, 1\leq l_1<l_2<\cdots<l_t\leq n-1$, of directed diagonals within an $n$-gon such that $l_1+\cdots+l_t\neq 0 \pmod n)$. Does it exist a directed path within the n-gon using each of the given lengths exactly once (and no vertex twice)?

Here the length of a directed diagonal within any kind of an n-gon is the number of sides of the n-gon between the starting and the end vertex counted in a fixed direction. A directed path is a sequence $(d_1,d_2,\ldots,d_t)$ of directed diagonals such that the end vertex of $d_i$ is the starting vertex of $d_{i+1}$ for $i=1,2,…,t-1$.

In number theory, it is equivalent to: For any subset $S=\{l_1,\ldots,l_t\}$ of $\{1,2,…,n-1\}$ with $ l_i, 1\leq l_1<l_2<\cdots<l_t\leq n-1$ and $l_1+\cdots+l_t\neq 0 \pmod n$. Is there any a permutation of the elements of the subset $S$ such that no set of consecutive elements in this permutation has sum $=0 \pmod n$. Can anyone give me a counter-example or prove it?

In Graph theory, I can rephrase this question to: Let $\mathbb{Z}_n$ be a group of integers modulo $n$ and $S=\{l_1,\dots,l_t\}$ be a set of positive integers such that $1\le l_1<l_2< \dots < l_t \le n-1$, where $l_1+\dots + l_t \not\equiv 0 \pmod n$).

Let $P_t$ be a directed path of length $t$ ($t+1$ vertices). Can you label the vertices of the directed path $\overrightarrow{P_t}$ of length $t$ with distinct elements of $\mathbb{Z}_n$ such that the label differences on edges are exactly $S$? The difference is taking by subtract the head by the tail (then take mod $n$).

I have a proof for case $t\leq 6$. However, I wonder is it true or not in general. Many thanks.

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Yoav Kallus
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Given $n$ and $t$ lengths $ l_i, 1\leq l_1<l_2<\cdots<l_t\leq n-1$, of directed diagonals within an $n$-gon such that $l_1+\cdots+l_t\neq 0 (mod n)$$l_1+\cdots+l_t\neq 0 \pmod n)$. Does it exist a directed path within the n-gon using each of the given lengths exactly once (and no vertex twice)?

Here the length of a directed diagonal within any kind of an n-gon is the number of sides of the n-gon between the starting and the end vertex counted in a fixed direction. A directed path is a sequence $(d_1,d_2,\ldots,d_t)$ of directed diagonals such that the end vertex of $d_i$ is the starting vertex of $d_{i+1}$ for $i=1,2,…,t-1$.

In number theory, it is equivalent to: For any subset $S=\{l_1,\ldots,l_t\}$ of $\{1,2,…,n-1\}$ with $ l_i, 1\leq l_1<l_2<\cdots<l_t\leq n-1$ and $l_1+\cdots+l_t\neq 0 (mod n)$$l_1+\cdots+l_t\neq 0 \pmod n$. Is there any a permutation of the elements of the subset $S$ such that no set of consecutive elements in this permutation has sum $=0 (mod n)$$=0 \pmod n$. Can anyone give me a counter-example or prove it?

In Graph theory, I can rephrase this question to: Let $\mathbb{Z}_n$ be a group of integers modulo $n$ and $S=\{l_1,\dots,l_t\}$ be a set of positive integers such that $1\le l_1<l_2< \dots < l_t \le n-1$, where $l_1+\dots + l_t \not\equiv 0$ (mod $n$$l_1+\dots + l_t \not\equiv 0 \pmod n$).

Let $P_t$ be a directed path of length $t$ ($t+1$ vertices). Can you label the vertices of the directed path $\overrightarrow{P_t}$ of length $t$ with distinct elements of $\mathbb{Z}_n$ such that the label differences on edges are exactly $S$? The difference is taking by subtract the head by the tail (then take mod $n$).

I have a proof for case $t\leq 6$. However, I wonder is it true or not in general. Many thanks

Given $n$ and $t$ lengths $ l_i, 1\leq l_1<l_2<\cdots<l_t\leq n-1$, of directed diagonals within an $n$-gon such that $l_1+\cdots+l_t\neq 0 (mod n)$. Does it exist a directed path within the n-gon using each of the given lengths exactly once (and no vertex twice)?

Here the length of a directed diagonal within any kind of an n-gon is the number of sides of the n-gon between the starting and the end vertex counted in a fixed direction. A directed path is a sequence $(d_1,d_2,\ldots,d_t)$ of directed diagonals such that the end vertex of $d_i$ is the starting vertex of $d_{i+1}$ for $i=1,2,…,t-1$.

In number theory, it is equivalent to: For any subset $S=\{l_1,\ldots,l_t\}$ of $\{1,2,…,n-1\}$ with $ l_i, 1\leq l_1<l_2<\cdots<l_t\leq n-1$ and $l_1+\cdots+l_t\neq 0 (mod n)$. Is there any a permutation of the elements of the subset $S$ such that no set of consecutive elements in this permutation has sum $=0 (mod n)$. Can anyone give me a counter-example or prove it?

In Graph theory, I can rephrase this question to: Let $\mathbb{Z}_n$ be a group of integers modulo $n$ and $S=\{l_1,\dots,l_t\}$ be a set of positive integers such that $1\le l_1<l_2< \dots < l_t \le n-1$, where $l_1+\dots + l_t \not\equiv 0$ (mod $n$).

Let $P_t$ be a directed path of length $t$ ($t+1$ vertices). Can you label the vertices of the directed path $\overrightarrow{P_t}$ of length $t$ with distinct elements of $\mathbb{Z}_n$ such that the label differences on edges are exactly $S$? The difference is taking by subtract the head by the tail (then take mod $n$).

I have a proof for case $t\leq 6$. However, I wonder is it true or not in general. Many thanks

Given $n$ and $t$ lengths $ l_i, 1\leq l_1<l_2<\cdots<l_t\leq n-1$, of directed diagonals within an $n$-gon such that $l_1+\cdots+l_t\neq 0 \pmod n)$. Does it exist a directed path within the n-gon using each of the given lengths exactly once (and no vertex twice)?

Here the length of a directed diagonal within any kind of an n-gon is the number of sides of the n-gon between the starting and the end vertex counted in a fixed direction. A directed path is a sequence $(d_1,d_2,\ldots,d_t)$ of directed diagonals such that the end vertex of $d_i$ is the starting vertex of $d_{i+1}$ for $i=1,2,…,t-1$.

In number theory, it is equivalent to: For any subset $S=\{l_1,\ldots,l_t\}$ of $\{1,2,…,n-1\}$ with $ l_i, 1\leq l_1<l_2<\cdots<l_t\leq n-1$ and $l_1+\cdots+l_t\neq 0 \pmod n$. Is there any a permutation of the elements of the subset $S$ such that no set of consecutive elements in this permutation has sum $=0 \pmod n$. Can anyone give me a counter-example or prove it?

In Graph theory, I can rephrase this question to: Let $\mathbb{Z}_n$ be a group of integers modulo $n$ and $S=\{l_1,\dots,l_t\}$ be a set of positive integers such that $1\le l_1<l_2< \dots < l_t \le n-1$, where $l_1+\dots + l_t \not\equiv 0 \pmod n$).

Let $P_t$ be a directed path of length $t$ ($t+1$ vertices). Can you label the vertices of the directed path $\overrightarrow{P_t}$ of length $t$ with distinct elements of $\mathbb{Z}_n$ such that the label differences on edges are exactly $S$? The difference is taking by subtract the head by the tail (then take mod $n$).

I have a proof for case $t\leq 6$. However, I wonder is it true or not in general. Many thanks

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