Timeline for Non-algebraic K3 surfaces in characteristic $p$
Current License: CC BY-SA 3.0
10 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Nov 22, 2017 at 22:38 | vote | accept | Daniel Loughran | ||
Jun 15, 2015 at 23:19 | vote | accept | Daniel Loughran | ||
Nov 22, 2017 at 22:38 | |||||
Jun 15, 2015 at 16:56 | history | edited | Francesco Polizzi | CC BY-SA 3.0 |
added 4 characters in body
|
Jun 15, 2015 at 14:40 | history | edited | Francesco Polizzi | CC BY-SA 3.0 |
added 10 characters in body
|
Jun 15, 2015 at 14:24 | comment | added | pro | since the word "beginner" has been used, a link to a previous answer seems relevant (I didn't know beforehand that all complete regular local rings are pretty much all created equal) mathoverflow.net/a/191737/73972 | |
Jun 15, 2015 at 14:09 | history | edited | Francesco Polizzi | CC BY-SA 3.0 |
added 1 character in body
|
Jun 15, 2015 at 14:01 | comment | added | Francesco Polizzi | Right, good point. | |
Jun 15, 2015 at 13:59 | comment | added | David E Speyer | To add a useful comment for beginners: The big difference between $\mathbb{C}$ and $\mathbb{F}_p$ here is that we can talk about convergence of power series over $\mathbb{C}$. Thus, we can take the formal power series in the $x_i$ and plug in nonzero complex numbers to get non-algebraic $K_3$'s. Over $\mathbb{F}_p$, the power series still exist, but it doesn't make sense to evaluate them anywhere except at $0$. | |
Jun 15, 2015 at 13:47 | history | edited | Francesco Polizzi | CC BY-SA 3.0 |
deleted 5 characters in body
|
Jun 15, 2015 at 13:41 | history | answered | Francesco Polizzi | CC BY-SA 3.0 |