Timeline for Is this polynomial irreducible over the rationals?
Current License: CC BY-SA 3.0
5 events
when toggle format | what | by | license | comment | |
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Nov 27, 2016 at 9:55 | vote | accept | B. S. | ||
Jun 15, 2015 at 18:53 | comment | added | Michael Stoll | @BogdanSimeonov Eisenstein works because the extension ${\mathbb Q}(\cos (2\pi/p))/{\mathbb Q}$ is totally ramified at $p$ (it is the maximal real subfield of the $p$th cyclotomic field). | |
Jun 15, 2015 at 14:30 | comment | added | B. S. | Thanks!It still remains a mystery why Eisenstein works here, I would love to see someone post a solution using it. | |
Jun 15, 2015 at 11:51 | history | edited | Gabriel Dill | CC BY-SA 3.0 |
inserted the forgotten i in the exponents...
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Jun 15, 2015 at 9:13 | history | answered | Gabriel Dill | CC BY-SA 3.0 |