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Jul 20, 2015 at 1:39 comment added hengxin Please check 1507.01663; link.
Jul 19, 2015 at 19:26 comment added esg I haven't found your paper. Is it on the arXiv yet?
Jul 7, 2015 at 7:30 comment added hengxin I have integrated your result here into a paper (which will be available at arXiv in two days). Now I cite your contributions through the link to this MO problem. What else should I do? If you want to obtain a copy of the paper or have any questions, please feel free to contact me. (You can find my email in my profile.) Thanks a lot.
Jun 14, 2015 at 14:49 comment added esg You clearly can still reduce to a one-dimensional integral, but because here the integrand changes at $s=t$ I don't expect an explicit formula in terms of classical functions.
Jun 14, 2015 at 8:13 comment added hengxin For the case of $D'_i > D_i - t$ ($t \ge 0$), the corresponding probability $\mathbb{P}(D'_i > x_i - t)$ depends on the relation between $x_i$ and $t$: if $x_i - t \ge 0$, it is $e^{\mu_1(t-x_i)}$; otherwise, it is $1$. How should I take into account both cases in the calculations? My basic idea is to integrate each $x_i$ over $[t,s]$ and $s$ over $[t,\infty[$. However, can we still obtain an explicit formula for this case? What do you think of it? Thanks.
S Jun 14, 2015 at 7:53 history suggested hengxin CC BY-SA 3.0
typo in $I_1$: missing $\mu_1$; little typo: independence
Jun 14, 2015 at 6:49 review Suggested edits
S Jun 14, 2015 at 7:53
Jun 14, 2015 at 6:33 comment added hengxin What if I interchange $t$ with $−t$ from the beginning (i.e., $D'_i > D_i - t$ now)? It seems that in the final result only $t$ needs to be changed to $−t$. However, this may give probability values larger than 1. Could you please give me some suggestions? Thanks.
Jun 13, 2015 at 2:01 vote accept hengxin
Jun 12, 2015 at 20:36 history answered esg CC BY-SA 3.0