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Jun 11, 2015 at 5:54 vote accept TCS-user-23
Jun 10, 2015 at 12:45 comment added Thomas Bloom Corrected, thanks! (I also realised that technically the $k$ needs shifting up by 1, if we're considering a graph that is not $k$-colourable.
Jun 10, 2015 at 12:45 history edited Thomas Bloom CC BY-SA 3.0
added 105 characters in body
Jun 10, 2015 at 12:22 comment added domotorp Not like it would change the order of magnitude from $\Theta(k^3)$, but your upper bound is not optimal, it should be ${2k-1\choose 3}$.
Jun 10, 2015 at 12:21 history edited Thomas Bloom CC BY-SA 3.0
More explicit bounds
Jun 9, 2015 at 22:23 history answered Thomas Bloom CC BY-SA 3.0