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Sep 26, 2021 at 17:13 history made wiki Post Made Community Wiki by Stefan Kohl
Mar 12, 2013 at 6:46 comment added Bad English Ryan Budney, as functor cohomology represented by spectra, but homology are not corepresented. May be this is first thing that literally does't have dual.
Apr 12, 2010 at 7:47 comment added Kevin H. Lin Harry, I'm not sure what you mean by that. If "cohomology in AG" means sheaf cohomology (a la Grothendieck), then sheaf cohomology does generalize singular cohomology: the sheaf cohomology of a constant sheaf on a locally contractible space is singular cohomology --- so even the notations agree!
Apr 10, 2010 at 4:58 comment added Ryan Budney Extraordinary cohomology theories are always dual to extraordinary homology theories. So your 2nd paragraph Anweshi isn't so much a special feature of cohomology.
Apr 10, 2010 at 2:41 comment added Tom Church You don't have a comultiplication on homology in general; see this question: mathoverflow.net/questions/415/does-homology-have-a-coproduct
Apr 10, 2010 at 1:53 comment added Mikael Vejdemo-Johansson Doesn't the comultiplication on homology provide exactly the same extra information as the multiplication on cohomology? The way I always understood it is that we prefer cohomology for algebra because corings are annoying to think about and work with...
Apr 10, 2010 at 1:52 comment added Harry Gindi The cohomology in algebraic geometry is not strictly a generalization.
Apr 10, 2010 at 1:44 history answered Anweshi CC BY-SA 2.5