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Apr 13, 2017 at 12:19 history edited CommunityBot
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Jul 27, 2015 at 8:59 vote accept Sven Wirsing
Jun 12, 2015 at 17:35 comment added Richard Stanley Following up on my previous comment, an interesting related result is that $\sum_\lambda f^\lambda (-1)^{\frac 12(n-\mathrm{rank}(\lambda))}$ equals the coefficient of $x^n/n!$ in $e^{x-\frac{x^2}{2}}$. Here $\lambda$ ranges over all self-conjugate partitions of $n$, $f^\lambda$ is the dimension of the corresponding symmetric group character, and $\mathrm{rank}(\lambda)$ is size of the Durfee square of $\lambda$ (the largest $i$ for which $\lambda_i\geq i$).
Jun 10, 2015 at 13:05 comment added Sven Wirsing Thank you, maybe its nice to know difference to the corresponding sum for $S_n$. Is this also in this tool?
Jun 8, 2015 at 17:00 answer added Stefan Kohl timeline score: 3
Jun 8, 2015 at 16:37 comment added Richard Stanley This is equivalent to finding the sum of the degrees of all self-conjugate characters of the symmetric group $S_n$. It appears in oeis.org/A067136, but I don't think that any reasonable formula is known.
Jun 8, 2015 at 13:14 history asked Sven Wirsing CC BY-SA 3.0