Timeline for Normalized tight frame that is not orthonormal
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Oct 1 at 13:37 | answer | added | Travis Bemrose | timeline score: 0 | |
| Jun 17, 2016 at 1:05 | answer | added | Melody | timeline score: 1 | |
| Jun 9, 2015 at 6:56 | comment | added | Jochen Wengenroth | My comment intended to show that the condition on the norms implies orthogonality. | |
| Jun 8, 2015 at 14:32 | comment | added | Mr.Wavelet | yes, there was a typo, but $\langle \psi_{m,n} , \psi_{j,k} \rangle = \delta_{m,j} \delta_{k,n}$ is only supposed to be true in the ONB case of couse and not for the case that I want to have an example for. | |
| Jun 8, 2015 at 14:30 | history | edited | Mr.Wavelet | CC BY-SA 3.0 |
added 2 characters in body
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| Jun 8, 2015 at 10:42 | comment | added | Jochen Wengenroth | You mean $\|f\|_2^2$, don't you? For $f=\psi_{m,n}$ you then get $\|\psi_{m,n}\|_2^2= \sum_{j,k} |\langle \psi_{m,n},\psi_{j,k}\rangle|^2 = \|\psi_{m,n}\|_2^2 + \sum_{(j,k)\neq (n,m)} |\langle \psi_{m,n},\psi_{j,k}\rangle|^2 $ so that $\langle \psi_{m,n},\psi_{j,k}\rangle=0$ for all $(j,k)\neq (n,m)$. | |
| Jun 7, 2015 at 16:09 | review | First posts | |||
| Jun 7, 2015 at 16:10 | |||||
| Jun 7, 2015 at 16:09 | history | asked | Mr.Wavelet | CC BY-SA 3.0 |