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Jun 6, 2015 at 15:53 comment added Elliot I think I have already proved (2) is ture ! The proof is not complex.
Jun 6, 2015 at 6:14 comment added Christian Remling @Q.L.Kwai: Express $\chi_{D_1\cup D_2}f$ in terms of $\chi_{D_j}f$.
Jun 6, 2015 at 3:11 comment added Elliot @Christian Remling:My friend,your comments may not make sure (2) is true. $int(D_{1})\cup int(D_{2})\subseteq int(D_{1}\cup D_{2})$ .Maybe some interior points of $D_{k}(k=1,2)$ at which $f$ is contionuous will become the discontionuos points of $f $ on $D_{1}\cup D_{2}$.
Jun 6, 2015 at 1:07 comment added Christian Remling (2) is true. Use that a function is R integrable precisely if it is bounded and continuous a.e.
Jun 5, 2015 at 2:45 comment added Elliot @David Roberts: Thanks for your mention.
Jun 5, 2015 at 2:43 comment added David Roberts Please don't use italic text inside colours inside maths environments for emphasis. Your message is not clearer for using many colours and fonts.
Jun 5, 2015 at 2:41 history edited David Roberts CC BY-SA 3.0
Fixed formatting.
Jun 5, 2015 at 2:06 review First posts
Jun 5, 2015 at 2:11
Jun 5, 2015 at 2:03 history asked Elliot CC BY-SA 3.0