Timeline for Is this differential identity known?
Current License: CC BY-SA 4.0
12 events
| when toggle format | what | by | license | comment | |
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| S Jan 5 at 7:51 | history | suggested | CommunityBot | CC BY-SA 4.0 |
somewhat better MathJax usage
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| Jan 5 at 6:52 | review | Suggested edits | |||
| S Jan 5 at 7:51 | |||||
| Jun 7, 2015 at 20:21 | answer | added | Iosif Pinelis | timeline score: 25 | |
| Jun 4, 2015 at 21:51 | comment | added | john mangual | These steampunk identities are really great. You can prove Rodriguez formula using matrix elements of $SO(3)$. | |
| Jun 4, 2015 at 2:15 | vote | accept | Terry Tao | ||
| Jun 4, 2015 at 2:13 | history | edited | Terry Tao | CC BY-SA 3.0 |
edited body
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| Jun 3, 2015 at 20:58 | answer | added | Robert Israel | timeline score: 34 | |
| Jun 3, 2015 at 20:08 | comment | added | Carlo Beenakker | If I'm not mistaken the formula as stated has a typo: $(k+1)/2$ in the denominator on the right-hand side should read $1+k/2$. (At least that's what the Rodrigues formula in my answer below would give.) | |
| Jun 3, 2015 at 19:48 | answer | added | Carlo Beenakker | timeline score: 89 | |
| Jun 3, 2015 at 16:35 | comment | added | Liviu Nicolaescu | The Fourier transforms of the distributions $(1+x^2)^\lambda$, $\lambda\in\mathbb{C}$, are studied in vol.1 of Gelfand and Shilov's book Generalized Functions, Chap.II, Sec. 2.6. The identity you discovered behaves nicely with respect to the Fourier transform and maybe it follows from the mountain of formulas in the above book. | |
| Jun 3, 2015 at 16:21 | comment | added | The Masked Avenger | Letting Q be $(1+x^2)^{1/2}$, I rewrite the identity using operator notation as Q^{k+1}D^{k+1}Q^k = C for a certain nonzero constant C. I then wonder if this is part of a larger total differential or perhaps the result of some inversion formula. Just some random musings, in case a random start toward an answer proves useful. | |
| Jun 3, 2015 at 16:06 | history | asked | Terry Tao | CC BY-SA 3.0 |