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Nov 17, 2015 at 19:19 history edited Anton Petrunin
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Sep 7, 2015 at 14:12 answer added Misha timeline score: 1
Jun 3, 2015 at 23:39 comment added Igor Rivin @HJRW Well, take a curve made of straight line segments of length $L$ meeting at angle $\pi -\epsilon.$ This will eventually close up into an $2N$-gon (for $\epsilon = \pi/N$), so is not a global quasi-geodesic no matter how large $L$ is, while being a local quasi-geodesic.
Jun 3, 2015 at 22:06 comment added HJRW What's the counterexample in the Euclidean plane? It's well known that global quasigeodesics there need not be uniformly close to a geodesic, but that's not quite the same thing...
Jun 3, 2015 at 15:09 history edited Igor Rivin CC BY-SA 3.0
fixed title
Jun 3, 2015 at 15:09 comment added Igor Rivin @HenrikRüping true, will fix.
Jun 3, 2015 at 5:19 comment added HenrikRüping So the question is about local quasigeodesics ? The title might suggest otherwise.
Jun 2, 2015 at 19:53 comment added Igor Rivin @LeeMosher Yes, as in Kent-Leininger...
Jun 2, 2015 at 19:24 comment added Lee Mosher I know examples of ping-pong type subgruops which are quasi-isometrically embedded, e.g. in mapping class groups, but the methods of proof that I know involve not-properly-discontinuous-but-otherwise-nice actions of the ambient group (or nondistorted subgroups thereof) on $\delta$-hyperbolic spaces.
Jun 2, 2015 at 16:48 history asked Igor Rivin CC BY-SA 3.0