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Apr 9, 2010 at 11:26 comment added Dror Speiser @Gerry: Both $A(x)$ and $B(x)$ are $\sim c_i x^2$ for some constants, and this will be true for any quadratic field, where constant will depend on discriminant, class number, and regulator. But, for a non-quadratic number field, the coefficients of the minimal polynomial of the generic number given in a $\mathbb{Q}$-basis, will be of high degree, and I can't see why the same asymptotic behavior should remain - even though it probably will.
Apr 8, 2010 at 23:39 comment added Gerry Myerson Have you tried a (possibly) simple case, like $K={\bf Q}(i)$?
Apr 8, 2010 at 23:08 history edited Dror Speiser CC BY-SA 2.5
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Apr 8, 2010 at 23:02 history edited Dror Speiser CC BY-SA 2.5
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Apr 8, 2010 at 22:53 history asked Dror Speiser CC BY-SA 2.5