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May 29, 2015 at 0:34 vote accept Sean Cox
May 28, 2015 at 23:52 answer added Joel David Hamkins timeline score: 8
May 28, 2015 at 22:00 comment added Ashutosh On Sh1036: I proof-read the current arxiv version (part of my job), and requested Shelah to make some changes. They should appear soon. I forgot to say that well-met condition does matter (forcing-wise). Assaf explains this well on his blogpost.
May 28, 2015 at 21:57 comment added Joel David Hamkins @AsafKaragila I'm not sure. I don't know of any arguments like that.
May 28, 2015 at 21:39 comment added Ashutosh These could be relevant: Sh1036 and Assaf's blogpost blog.assafrinot.com/?p=3841
May 28, 2015 at 21:36 comment added Asaf Karagila @Joel: Is it possible to characterize these sort of failures? Namely, "if $A\subseteq\mathcal B(\Bbb P)$ is a counterexample to some closure property of $\Bbb P$, then ..." or something like that?
May 28, 2015 at 21:15 comment added Noah Schweber Ah, quite right - that's clear in retrospect, I'm tired today.
May 28, 2015 at 21:11 comment added Joel David Hamkins @NoahSchweber No infinite complete Boolean algebra is even countably closed, since there must be countably infinite antichains, and you can make an $\omega$-descending sequence by joining the tail starting further and further out. These meet to zero, so the algebra is not countably closed.
May 28, 2015 at 21:08 comment added Noah Schweber Can you explain how the Boolean closure messes up $\lambda$-directed closedness? I'm not seeing it . . .
May 28, 2015 at 20:55 comment added Asaf Karagila It sounds weird that Boolean completions can screw up closure properties.
May 28, 2015 at 20:46 history asked Sean Cox CC BY-SA 3.0